181.超过经理收入的员工

题目描述

表：Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
id 是该表的主键（具有唯一值的列）。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

编写解决方案，找出收入比经理高的员工。

以 任意顺序 返回结果表。

结果格式如下所示。

示例 1:

输入: 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
输出: 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
解释: Joe 是唯一挣得比经理多的雇员。

SQL Schema

DROP TABLE IF EXISTS Employee;
Create table If Not Exists Employee
(
    id        int,
    name      varchar(255),
    salary    int,
    managerId int
);
insert into Employee (id, name, salary, managerId)
values ('1', 'Joe', '70000', '3');
insert into Employee (id, name, salary, managerId)
values ('2', 'Henry', '80000', '4');
insert into Employee (id, name, salary, managerId)
values ('3', 'Sam', '60000', NULL);
insert into Employee (id, name, salary, managerId)
values ('4', 'Max', '90000', NULL);

答案

SELECT e.name AS `Employee`
FROM employee e
         INNER JOIN employee m ON e.managerId = m.id
WHERE e.salary > m.salary;