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SQL201 查找薪水记录超过15条的员工号emp_no以及其对应的记录次数t

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题目描述

有一个薪水表,salaries简况如下:

emp_nosalaryfrom_dateto_date
10001601171986-06-261987-06-26
10001621021987-06-261988-06-25
10001660741988-06-251989-06-25
10001665961989-06-251990-06-25
10001669611990-06-251991-06-25
10001710461991-06-251992-06-24
10001743331992-06-241993-06-24
10001752861993-06-241994-06-24
10001759941994-06-241995-06-24
10001768841995-06-241996-06-23
10001800131996-06-231997-06-23
10001810251997-06-231998-06-23
10001810971998-06-231999-06-23
10001849171999-06-232000-06-22
10001851122000-06-222001-06-22
10001850972001-06-222002-06-22
10002725271996-08-031997-08-03

请你查找薪水记录超过15条的员工号emp_no以及其对应的记录次数t,以上例子输出如下:

emp_not
1000116

SQL Schema

sql
drop table if exists  `salaries` ; 
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
INSERT INTO salaries VALUES(10001,60117,'1986-06-26','1987-06-26');
INSERT INTO salaries VALUES(10001,62102,'1987-06-26','1988-06-25');
INSERT INTO salaries VALUES(10001,66074,'1988-06-25','1989-06-25');
INSERT INTO salaries VALUES(10001,66596,'1989-06-25','1990-06-25');
INSERT INTO salaries VALUES(10001,66961,'1990-06-25','1991-06-25');
INSERT INTO salaries VALUES(10001,71046,'1991-06-25','1992-06-24');
INSERT INTO salaries VALUES(10001,74333,'1992-06-24','1993-06-24');
INSERT INTO salaries VALUES(10001,75286,'1993-06-24','1994-06-24');
INSERT INTO salaries VALUES(10001,75994,'1994-06-24','1995-06-24');
INSERT INTO salaries VALUES(10001,76884,'1995-06-24','1996-06-23');
INSERT INTO salaries VALUES(10001,80013,'1996-06-23','1997-06-23');
INSERT INTO salaries VALUES(10001,81025,'1997-06-23','1998-06-23');
INSERT INTO salaries VALUES(10001,81097,'1998-06-23','1999-06-23');
INSERT INTO salaries VALUES(10001,84917,'1999-06-23','2000-06-22');
INSERT INTO salaries VALUES(10001,85112,'2000-06-22','2001-06-22');
INSERT INTO salaries VALUES(10001,85097,'2001-06-22','2002-06-22');
INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'1996-08-03','1997-08-03');

答案

sql
SELECT emp_no, COUNT(*) AS `t`
FROM salaries
GROUP BY emp_no
HAVING t > 15;