SQL209 查找employees表emp_no与last_name的员工信息

题目描述

有一个员工表employees简况如下:

emp_no	birth_date	first_name	last_name	gender	hire_date
10001	1953-09-02	Georgi	Facello	M	1986-06-26
10002	1964-06-02	Bezalel	Simmel	F	1985-11-21
10003	1959-12-03	Bezalel	Mary	M	1986-08-28
10004	1954-05-01	Christian	Koblick	M	1986-12-01
10005	1953-11-07	Mary	Sluis	F	1990-01-22

请你查找employees表所有emp_no为奇数，且last_name不为Mary的员工信息，并按照hire_date逆序排列，以上例子查询结果如下:

emp_no	birth_date	first_name	last_name	gender	hire_date
10005	1953-11-07	Mary	Sluis	F	1990-01-22
10001	1953-09-02	Georgi	Facello	M	1986-06-26

SQL Schema

drop table if exists  `employees` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Bezalel','Mary','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1953-11-07','Mary','Sluis','F','1990-01-22');

答案

SELECT *
FROM employees
WHERE emp_no % 2 <> 0
  AND last_name <> 'Mary'
ORDER BY hire_date DESC;